If sin θ = 3/5 and θ is acute, find cos θ.
- A3/5
- B4/5
- C5/3
- D5/4
Reveal answer
Correct answer
B.4/5
Reveal solution
cos²θ = 1 − sin²θ = 1 − 9/25 = 16/25, so cos θ = 4/5.
If sin θ = 3/5 and θ is acute, find cos θ.
cos²θ = 1 − sin²θ = 1 − 9/25 = 16/25, so cos θ = 4/5.